The San Francisco 49ers narrowly missed out on winning the Super Bowl LIV in Miami last year. Kyle Shanahan and Co. were outplayed in the final quarter of the game at the hands of a determined Patrick Mahomes who bagged the Super Bowl LIV MVP award as well. Despite that heartbreak, the 49ers start 2020 as one of the favorite challengers for the Lombardi Trophy once again. One of the positives for the 49ers last time out was their D-line. However, Jimmy Garoppolo, Deebo Samuel, and George Kittle were the shining lights in Kyle Shanahan’s offense back then.
Kittle has entered the final year of his rookie contract in 2020. He is in line for a bumper contract extension in the coming weeks. The only question that remains is, how much will the 49ers be willing to pay their star player?
George Kittle was arguably the best player for the 49ers last season. The 26-year old has more than 80+ receptions and 1,000+ receiving yards in the last two years. He missed two games in 2019 due to a foot injury.
As per his current contract, Kittle stands to earn a minuscule $2.3 million for the 2020 season. However, he is definitely in line for a mega-contract extension as the 49ers aim for glory once again. Carolina Panthers WR Christian McCaffrey and Kansas City Chiefs QB Patrick Mahomes’ contract extension were the two big-money deals this year.
Kittle’s agent, Jack Bechta will use these two deals as references while negotiating an extension for his client. Of course, the TE market is different than that for a WR or a QB. Los Angeles Chargers’ Hunter Henry is the highest-earning TE in the League at the moment with a $10.6 million franchise tag contract. Cleveland Browns’ Austin Hooper is second on the list. He signed a four-year deal worth $42 million deal which amounts to $10.5 million per year.
We expect that the 49ers will offer Kittle a deal that is superior to both the players mentioned above. At the end of the day, he is the top tight end in the League for now, ahead of the Chiefs’ Travis Kelce.
SOURCE: 49ers on NBCS Twitter